Question

A body whose 6kg is acted upon by two forces (8i+10j)N and (4i+8j)N. the acceleration produced will be_​

Answer 1

Answer:

2i + 3j

Explanation:

F1 = 8i + 10j

F2 = 4i + 8j

Fnet = F1 + F2 = 12i + 18j

also, F = ma

so, a = F/m

a = (12i + 18j)/6 = 2i + 3j

magnitude is √4+9 = √13