A body whose initial velocity 2m/s travels with 2m/s² acceleration then find velocity after covering 6m distance.
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Answered by
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Explanation:
U= 2m/s
a= 2m/s²
S= 6 m
V=?
v²= u²+2as
v²= 4+ 2×2×6
v²= 28
v = 2 root 7
Answered by
0
Explanation:
here U =2m/s
S=6m
and a=2m/s²
v²=U²+2as
=>v²=4m²/s²+24m²/s²
=>v²=28m²/s²
=>v=√28m²/s²
=>v=2√7m/s...........
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