Question

A body whose initial velocity is 20m/s moves for 4s in a straight line with an acceleration of 5m/s2 and then retarded at 10m/s2. Calculate the total distance covered before it comes to rest

Answer 1

Step-by-step explanation:

Here, Initial velocity=u=20

Time taken =4s=t

Acceleration=5=a

s =ut+1/2at^2

So 20 x 4+1/2x5x16

=80+40

=120 m

Acceleration=-10

S=ut+1/2at^2

0

So distance =120 m