Question

a body whose mass is 3 kg performs a linear motion according to the formula S is equal to 1 + t + t^2 where as mentioned in centimetre and t in second determine the kinetic energy 1 / 2 Mv^2of the body 5 seconds after it starts​

Answer 1

Answer:

The kinetic energy of the body after 5 seconds is 181.5 Joules.

Explanation:

Step 1 : Given the displacement function S we can get the velocity function.

S = 1 + t + t²

To get the velocity function, we will differentiate S with respect to t.

That is :

dS/dt = 0 + 1 + 2t = V

Therefore :

V = 2t + 1

Step 2 : from the velocity function we can calculate the velocity after 5 seconds.

t = 5

V = 2t + 1 = 2 × 5 + 1 = 11 m/s

Step 3 : We now need the kinetic energy.

KE = ½mv²

m = 3 kg

V = 11

Substituting we have :

KE = ½ × 3 × 11² = 181.5 Joules.

Answer 2

Answer:

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Explanation:

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