a body whose mass is 4.0kg falls freely from the height of 12m from the rest position find the intial potential energy,kinetic energy at a height of 8m and total energy of the body.(g=10m/second square.
Answers
Answered by
7
Mass = 4.0 kg
height= 12m
u= 0m/s
g= 10m/s2
initial potential energy= MGH
= 4×10×12
= 480J
kinetic energy at the height of 8m
= 1/2mv2
v=?
2as= v2 - u2
2×10×8= v2- (0)2
160= v2-0
v2= 160
v= √160
Kinetic energy=
1/2mv2
= 1/2× 4× (√160)2
= 2× 160
= 320J
Total energy= 320J + 480J
= 800J
Similar questions