Physics, asked by Chimpindebanda, 1 year ago

A body whose mass is 6kg is acted on by a force which changes it's velocity from 3ms-1 to 5 ms-1. Find the impulse of the force. If the force is acted for 2 seconds .find the force in Newton .

Answers

Answered by kvnmurty
0
m = 6 kg
p2 - p1 = m v2 - m v1 = 6 (5-3) = 12 kg-m/sec

Impulse is equal to change in momentum = 12 kg -m /sec
force = impulse / time duration = 12/2 = 6 N

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