Question

A body whose moment of inertia is 3 kgm^2 is at rest. It rotates for 20s with a moment of force 6NM. FInd the angular displacement of the body. Calculate the workdone.

Answer 1

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Answer 2

Dear Student,

◆ Answer -

θ = 400 rad

W = 2400 J

● Explanation -

# Given -

I = 3 kgm^2

t = 20 s

τ = 6 Nm

# Solution -

Angular acceleration of the body is -

α = τ/I

α = 6/3

α = 2 rad

Angular displacement is now calculated as -

θ = αt²/2

θ = 2×20²/2

θ = 400 rad

Work done by the body is given by -

W = τ.θ

W = 6 × 400

W = 2400 J

Hence, work done by the body is 2400 J.

Thanks dear. Hope this helps you..