a body with a velocity of 18 kmh-1 accelerates uniformly at the rate of 9 cms-2 over a distance of 200 m. calculate: the acceleration and final velocity.
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Initial Velocity= 18 km/h = 5 m/s
Acceleration = 9 cm/s² = 0.09m/s²
Distance = 200 m
By the second equation of motion, we have s = v² - u²/2a
∴ v² = u² + 2as = 5² + 2×0.09×200 = 61
∴v = √61 ≈ 7.81 m/s
Acceleration = 9 cm/s² = 0.09m/s²
Distance = 200 m
By the second equation of motion, we have s = v² - u²/2a
∴ v² = u² + 2as = 5² + 2×0.09×200 = 61
∴v = √61 ≈ 7.81 m/s
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