a body with an initial velocity of 18 km per hour accelerates uniformly at the rate of 9 CM square over the distance of 200 calculate the acceleration in metre second square second its final velocity in metre second
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13
Given, u=18km/h
18*1000/3600 m/s= 5m/s
a=9cm/s² = 9*0.01 m/s² = 0.09m/s²
s=200m
v=?
v²=u²+2as
v²=5²+2(0.09)(200)
v²=25+36
v²=61
v=√61=7.81 m/s
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2
Answer:
625m
Explanation:
The initial velocity is u=0ms−1
The acceleration is a=10ms−2
The time is t=5s
Apply the equation of motion
v=u+at
The velocity is
v=0+10⋅5=50ms−1
The distance travelled in the first 5s is
s=ut+12at2
=0⋅5+12⋅10⋅52=125m
The distance travelled in the following 10s is
s1=vt1=50⋅10=500m
The total distance travelled is
d=s+s1=125+500=625m
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