A body with an initial velocity of 18 km per hour accelartes uniformly at the rate of 9 cm per second square over a distance of 200 meter. Calculate its final velovity in meter per second
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Answer:
u = 18km/hr or 18×5/18 = 5m/s
a= 9cm/s^2 or 9/100m/s^2
s = 200m
equation of motion-
v^2 = u^2 +2as
= (5)^2 +2(9/100×200)
= 25+36
v^2 = 61
v = √61
v = 7.8 m/s
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Answered by
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a = 9cm/s ^2 = 9/100= 0.09 m/s
U = 18 km/h = 18*1000/60*60 = 180/36 = 10/2 = 5 m/s
S = 200 m
V =?
V^2 - U^2 = 2as
V^2 = 2*0.9*200+5^2
V^2 = 36+25
V^2 = 61
V = √61
V = Final velocity= 7.81 m/s (approx)
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