Physics, asked by mohansah986, 9 months ago

A body with an initial velocity of 18 km per hour accelartes uniformly at the rate of 9 cm per second square over a distance of 200 meter. Calculate its final velovity in meter per second​

Answers

Answered by BrainlyNidhi
2

Answer:

u = 18km/hr or 18×5/18 = 5m/s

a= 9cm/s^2 or 9/100m/s^2

s = 200m

equation of motion-

v^2 = u^2 +2as

= (5)^2 +2(9/100×200)

= 25+36

v^2 = 61

v = √61

v = 7.8 m/s

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Answered by Anonymous
2

a = 9cm/s ^2 = 9/100= 0.09 m/s

U = 18 km/h = 18*1000/60*60 = 180/36 = 10/2 = 5 m/s

S = 200 m

V =?

V^2 - U^2 = 2as

V^2 = 2*0.9*200+5^2

V^2 = 36+25

V^2 = 61

V = √61

V = Final velocity= 7.81 m/s (approx)

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