Question

A body with an initial velocity of 18 kmh–1 accelerates uniformly at the rate of 9 cms–2 cover a distance
of 200 m. Calculate :
(i) the acceleration in ms–2
(ii) the final velocity in ms–1

Answer 1

7.81

Given, initial velocity u=18kmh  

−1

 

                                      =  

60×60

18000m

​

=5ms  

−1

 

Acceleration a=0.09ms  

−2

 

and distance s = 200 m

From equation of motion v  

2

=u  

2

+2as,

We get, v=  

5  

2

+2×0.09×200

​

m/s=7.81m/s