Question

A body with an initial velocity of 3 m s^-1 moves with
an acceleration of 2 m s^-2. Then the distance
travelled in the 4th second is:
(a) 10
(b) 6
(c) 7
(d) 28
(please don't give irrelevent answers )​

Answer 1

Answer:

28 m

Explanation:

s = ut + 1/2 at^2

s = 3 × 4 + 1/2×2×(4)^2

s = 12 + 16

s = 28 m