A body with an initial velocity of 36 km/h accelerates uniformly at the rate of 9 cm/s2 over a distance of 200 m. Calculate : a) the acceleration in m/s2 . b) its final velocity in m/s.
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Answered by
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Answer:
Given, initial velocity u=18kmh
−1
=
60×60
18000m
=5ms
−1
Acceleration a=0.09ms
−2
and distance s = 200 m
From equation of motion v
2
=u
2
+2as,
We get, v=
5
2
+2×0.09×200
m/s=7.81m/s
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