Question

A body with an initial velocity of 36 kmph accelerates uniformly at the rate of 4m/s² for 15 seconds. Calculate the total distance travelled in 20 sec and the final velocity?​

Answer 1

Answer:

u = 36 km/hr = 10m/s

a = 4m/s2

t=15s

a = \frac{v - u}{t}a=

t

v−u

4 = \frac{v - 10}{15}4=

15

v−10

4×15=v-10

60=v-10

60+10=v

70m/s=v

Now

\begin{gathered}s = ut + \frac{1}{2} a {t}^{2} \\ s = 10 \times 15 + \frac{1}{2} \times 4 \times {15}^{2} \\ s = 150 + 2 \times 225 \\ s = 150 + 450 \\ s = 600m\end{gathered}

s=ut+

2

1

at

2

s=10×15+

2

1

×4×15

2

s=150+2×225

s=150+450

s=600m