A body with an initial velocity of 3m/s moves with an acceleration of 2m/s^2.Then the distance traveled in the 4th second is ?
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Answered by
10
Answer:
hopefully it will help u
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ishitasoryan123:
As you have written 3+1 (7)
How can the answer be10
It will be like this I think 4 (7)=28 not 10
Please check once and don't think I am saying that this is wrong
no dear.first u have to multiply 7*1
then 3+7
i hope now u r getting this..or will i explain more?
Answered by
5
Answer:
when t =4
s = ut + 0.5 x at²
s=3 x 4 + 0.5 x 2 x 4²
s= 12 + 16
s= 28m
when t= 3
s= ut + 0.5 x at²
s= 3 x 3 + 0.5 x 2 x 3²
s= 9 + 9
s= 18m
thus the distance travelled in the 4 second = Total distance in 4 second - total distance in 3 second
=28-18
=10m
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