Question

a body with an initial velocity of 8 m/s accelerates at the rate of 9 cm-2. if the distance covered by the body is 200.caluclate the time taken to cover the given distance​

Answer 1

Explanation:

initial velocity u=18kmh

−1

=

60×60

18000m

=5ms

−1

Acceleration a=0.09ms

−2

and distance s = 200 m

From equation of motion v

2

=u

2

+2as,

We get, v=

5

2

+2×0.09×200

m/s=7.81m/s