Question

A body with an initial velocity of 8m/s accelerates at the rate of 9cms-2. If the distance covered by the body is 200m, calculate the time taken to cover the given distance

Answer 1

Answer:

v=8c/m

a=9cm/s2

d=200m

s=ut+1/2at^2

200=0+1/2*0.09*t^2

t^2=400/0.09

t=20/0.3=200/3

Answer 2

Given:

Initial velocity of the body = 8 m/s

Acceleration of the body = 9 cm/s² = 0.09 m/s²

Distance covered by the body = 200 m

To find:

The time taken to cover the distance

Calculation:

From equations of motion, we have

  S=ut+(1/2)at²

By substituting the values in the formula

=> 200 = (8×t) + (1/2)×0.09×t²

     200 = 8t + 0.045t²

     0.045t²+8t-200 = 0

     t = 22.22 s, t = -200 s

As time cannot take negative values, t = 22.22 sec

Final answer:

The time taken by the body to cover the distance is 22.22 sec