A body with an initial velocity of 8m/s accelerates at the rate of 9cms-2. If the distance covered by the body is 200m, calculate the time taken to cover the given distance
Answers
Given : A body with an initial velocity of 8m/s accelerates at the rate of 9cms-2. he distance covered by the body is 200m,
To find : time taken to cover the given distance
Solution:
Initial velocity u = 8 m/s
acceleration a = 9 cm/s² = 0.09 m/s²
Distance covered S = 200 m
S = ut + (1/2)at²
=> 200 = 8t + (1/2)(0.09)t²
=> 0.045t² + 8t - 200 = 0
=> t = (- 8 + √(8² - 4(0.045)(-200)) )/( 2 * 0.045)
( -ve value is ignored and only positive is considered)
=> t = 2/0.09
= > t = 200/9 sec
time taken to cover the given distance = 200/9 sec
= 22.222 sec
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