Physics, asked by fltrpjminie, 7 months ago

A body with an initial velocity of 8m/s accelerates at the rate of 9cms^-2. If the distance covered by the body is 200m, calculate the time taken to cover the given distance.

Answers

Answered by nandinijagwani15

V=8c/m

V=8c/ma=9cm/s²

V=8c/ma=9cm/s²d=200m

V=8c/ma=9cm/s²d=200m s=ut+1/2at^2

***V=8c/ma=9cm/s²d=200m s=ut+1/2at^2200=0+1/20.09t^2***

***V=8c/ma=9cm/s²d=200m s=ut+1/2at^2200=0+1/20.09t^2t^2=400/0.09***

***V=8c/ma=9cm/s²d=200m s=ut+1/2at^2200=0+1/20.09t^2t^2=400/0.09t=20/0.3=200/3***

Answered by freedarajesh2003

Answer:

Explanation:

V=8c/m

V=8c/ma=9cm/s²

V=8c/ma=9cm/s²d=200m

V=8c/ma=9cm/s²d=200m s=ut+1/2at^2

V=8c/ma=9cm/s²d=200m s=ut+1/2at^2200=0+1/2*0.09*t^2

V=8c/ma=9cm/s²d=200m s=ut+1/2at^2200=0+1/2*0.09*t^2t^2=400/0.09

V=8c/ma=9cm/s²d=200m s=ut+1/2at^2200=0+1/2*0.09*t^2t^2=400/0.09t=20/0.3=200

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A body with an initial velocity of 8m/s accelerates at the rate of 9cms^-2. If the distance covered by the body is 200m, calculate the time taken to cover the given distance.​

Answers

V=8c/m

V=8c/ma=9cm/s²

V=8c/ma=9cm/s²d=200m

V=8c/ma=9cm/s²d=200m s=ut+1/2at^2

V=8c/ma=9cm/s²d=200m s=ut+1/2at^2200=0+1/2*0.09*t^2

V=8c/ma=9cm/s²d=200m s=ut+1/2at^2200=0+1/2*0.09*t^2t^2=400/0.09

V=8c/ma=9cm/s²d=200m s=ut+1/2at^2200=0+1/2*0.09*t^2t^2=400/0.09t=20/0.3=200/3

A body with an initial velocity of 8m/s accelerates at the rate of 9cms^-2. If the distance covered by the body is 200m, calculate the time taken to cover the given distance.

***V=8c/ma=9cm/s²d=200m s=ut+1/2at^2200=0+1/20.09t^2***

***V=8c/ma=9cm/s²d=200m s=ut+1/2at^2200=0+1/20.09t^2t^2=400/0.09***

***V=8c/ma=9cm/s²d=200m s=ut+1/2at^2200=0+1/20.09t^2t^2=400/0.09t=20/0.3=200/3***