a body with initial velocity 3 metre per second move with the acceleration of 2 metre per second the distance travelled in 4 second is
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Second equation of motion is
S = ut +1(at2) /2
Given that : u=3m per second
a =2ms-2
So,
S =3*4+1(2*16) /2
S =50+1*32/2
S =50+16
S =66m
Answered by
11
Answer:
Your answer.
Step-by-step explanation:
The correct answer my will be 10m.
when time(t) = 4 sec
S=ut+1/2at² :here S is distance
U is initial velocity
a is acceleration
t is time(समय)
S= 3*4+0.5*2*4²
S= 12+16
S= 28m
When time(t) = 3 sec
S= ut+1/2at²
S= 3*3+0.5*2*3²
S= 9+9
S= 18m
So, distance travelled in 4th sec
= (28-18)m = 10m
Your final answer is 10m
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