A BODY WITH INITIAL VELOCITY 8 M/S MOVES ALONG A STRAIGHT LINE WITH CONSTANT ACCELERATION AND TRAVELS 640 M IN 40 S. FIND THE AVERAGE VELOCITY DURING THIS INTERVAL. ALSO FIND THE FINAL VELOCITY AND ACCELERATION
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74
here is ur answer, u=8m/s, t=40s, d=640m . so by the formula s= ut+1/2at^2 we will find acceleration . 640= 8×40+1/2×a×40×40= 640-320= 800a . 320/800=a. therefore a= 0.4m/s^2 . then find final velocity. v= u +at. v= 8+0.4×40 .v=24m/s. then average velocity = 640/40 =16m/s. THANKYOU
pritisingl1234:
THANKS
Answered by
12
Answer:
16m/s
Explanation:
average velocity:
total distance covered÷total time taken
given,s=640m,t=40seconds
640/40=16m/s....
hope it helps☺
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