Question

A body with mass 30kg with speed 20 m/s applied force 60n and how much does it takes to stop

Answer 1

Stopping distance = 
mu^{2} ÷2force 
30×20×20/2×60
=30×400/120
=1200/12
=100m

Stopping time = mu/force
=30×20/60
=600/60
=100 sec

Answer 2

Stopping distance = 
mu^{2} ÷2force 
30×20×20/2×60
=30×400/120
=1200/12
=100m

Stopping time = mu/force
=30×20/60
=600/60
=100 sec
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