A bol is released from a height of 1 meter. What time it will take to reach the surface of the earth?
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Step-by-step explanation:
Let the value of g be 10m/s²
Now
We know that,
v=u +at
v=0+10t (u=0 , as it is released from rest)
v=10t————eq 1
Now
v²=u²+2as
(10t)²=0+2*10*s. (using eq 1)
100t²=20——-(s=1m)
t=√(20/100)
t=√0.2 sec
hope it is helpful dear friend
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