Question

A bomb at rest explodes into three fragments of equal mass two fragments fly of right angle to each other with velocities 9m/s and 12m/s calculate the velocity of third fragments

Answer 1

The 3rd fragment flies at 15 m/s

We can answer this by momentum conservation

Since initial momentum is 0

The diagram is below

Taking resultant for perpendicular parts we get root (225)=15

Since momentum =0 the

Velocity of 3rd should be opposite and equal to resultant

So answer is -15m/s

Answer 2

\pi \: r3 it is right answer