Question

a bomb at rest explodes into three fragments of mass 1:2:3. the fragments having lighter masses moves with the speed of 40m/s mutually perpendicular to each other. calculate v3(velocity of third part)?

Answer 1

For simplicity we take m1=1 kg, m2=2 kg and m3= 3kg.

We assume that the bomb is at rest initially, and P1, P2 and P3 are the momentum (as vectors) or the 3 masses after explosion. The law of the conservation of total linear momentum before and after explosion can be written as

0 = P1+P2+P3so that P3= -(P1 +P2)

and in absolute value

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