a bomb dipped from an jet plane when it is directly above a target at a height of 1500 m. the jet plane is joining horizontally with a speed of 500 km/h.By how much distance will the bomb miss the target??
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Time t to reach the ground is given by
h = u t + 1/2 g t²
1500 = 0 + 1/2 * 10 * t² , as g = 10 m/sec²
t = √300 = 10√3 sec = 17.32 sec
Horizontal distance travelled by the bomb from the point of release from the Jet plane = horizontal uniform velocity * time travelled
= 500 km / hr * 17.32 sec = 500 * 5/18 * 17.32 = 2, 405.55 meters
= 2.405 km
h = u t + 1/2 g t²
1500 = 0 + 1/2 * 10 * t² , as g = 10 m/sec²
t = √300 = 10√3 sec = 17.32 sec
Horizontal distance travelled by the bomb from the point of release from the Jet plane = horizontal uniform velocity * time travelled
= 500 km / hr * 17.32 sec = 500 * 5/18 * 17.32 = 2, 405.55 meters
= 2.405 km
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