Question

a bomb dipped from an jet plane when it is directly above a target at a height of 1500 m. the jet plane is joining horizontally with a speed of 500 km/h.By how much distance will the bomb miss the target??

Answer 1

Time t  to reach the ground is given by 
 
      h = u t + 1/2  g  t² 
       1500 = 0 + 1/2  * 10 * t²         , as  g = 10 m/sec²

           t =  √300 = 10√3 sec = 17.32 sec
 
   Horizontal distance travelled by the bomb from the point of release from the Jet plane =  horizontal uniform velocity *  time travelled
         =  500 km / hr *  17.32 sec =  500 * 5/18 * 17.32 = 2, 405.55 meters
         = 2.405 km