Question

A bomb exploded in air when it has a horizontal speed of 100kmph.it break into two pieces A,B of mass ratio 1:2.if A goes vertically of speed 400kmph, the speed of B will be??

Answer 1

Answer:

250 m/s

Explanation:

Let mass of the bomb = 3 kg

Then mass of both parts - 1kg and 2kg

Initial momentum=Final momentum

3*100 î = 1*400 j + 2*v

300 î - 400 j = 2 v

500 = 2v

v= 250 m/s