A bomb explodes between two blocks. The coefficients of friction are U1 and U2. What will be the ratio of their stopping distances
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Let the two EQUAL blocks travel in opposite directions with equal velocity. Two Directions 1 and 2 have coefficient of friction μ1 and μ2 respectively.
Friction f = μ N = μ m g
Deceleration = f/m = μ g .
s = (v^2 - u^2)/(2a)
S1 = u^2 / (2 μ1 g)
S2 = u^2 / (2 μ2 g)
S1 : S2 = μ2 : μ1.
This ratio can be found from work done by friction. That is same as the initial KE.
W1/W2 = 1 = f1 s1 /( f2 s2)
S1 / s2 = μ2/ μ1
Friction f = μ N = μ m g
Deceleration = f/m = μ g .
s = (v^2 - u^2)/(2a)
S1 = u^2 / (2 μ1 g)
S2 = u^2 / (2 μ2 g)
S1 : S2 = μ2 : μ1.
This ratio can be found from work done by friction. That is same as the initial KE.
W1/W2 = 1 = f1 s1 /( f2 s2)
S1 / s2 = μ2/ μ1
kvnmurty:
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