A bomb is dropped directly above a height of 1000m speed of aeroplane is 500 km/hr. how much distance away the bomb will hit from the target?
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ime taken to reach the ground = √(2H/g)
= √(2 × 1000 / 10)
= √(200)
= 10√2 seconds
Distance = Velocity × Time
= (500 × 5/18 m/s) × 10√2 s
= 1964.1 m
= 1.964 km
The bomb wil miss the target by distance of 1.964 km
= √(2 × 1000 / 10)
= √(200)
= 10√2 seconds
Distance = Velocity × Time
= (500 × 5/18 m/s) × 10√2 s
= 1964.1 m
= 1.964 km
The bomb wil miss the target by distance of 1.964 km
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