Physics, asked by anubrata766493, 8 months ago

a bomb is dropped from an aircraft when it is directly above a target at a height of 1000m the aircraft is moving with a velocity of 500km/h by how much distance it will miss the target​

Attachments:

Answers

Answered by nishayadav4793
0

Answer:

d=1964.2m

Explanation:

Since the the aeroplane is directly above a target at a height of 1000 m, the distance by which bomb will miss the target is equal to the horizontal distance covered by bomb during its fall

Horizontal distance (d)= Time of fall × Horizontal speed

⇒d=t×v

⇒d=

g

2h

×500km/h

⇒d=

10

2×1000

×500×

18

5

m/s

⇒d=1964.2m

Answered by shashijayashri
1

Explanation:

Since the the aeroplane is directly above a target at a height of 1000 m, the distance by which bomb will miss the target is equal to the horizontal distance covered by bomb during its fall

Horizontal distance (d)= Time of fall × Horizontal speed

⇒d=t×v

⇒d=

g

2h

×500km/h

⇒d=

10

2×1000

×500×

18

5

m/s

⇒d=1964.2m

Similar questions