a bomb is dropped from an aircraft when it is directly above a target at a height of 1000m the aircraft is moving with a velocity of 500km/h by how much distance it will miss the target
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Answered by
0
Answer:
d=1964.2m
Explanation:
Since the the aeroplane is directly above a target at a height of 1000 m, the distance by which bomb will miss the target is equal to the horizontal distance covered by bomb during its fall
Horizontal distance (d)= Time of fall × Horizontal speed
⇒d=t×v
⇒d=
g
2h
×500km/h
⇒d=
10
2×1000
×500×
18
5
m/s
⇒d=1964.2m
Answered by
1
Explanation:
Since the the aeroplane is directly above a target at a height of 1000 m, the distance by which bomb will miss the target is equal to the horizontal distance covered by bomb during its fall
Horizontal distance (d)= Time of fall × Horizontal speed
⇒d=t×v
⇒d=
g
2h
×500km/h
⇒d=
10
2×1000
×500×
18
5
m/s
⇒d=1964.2m
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