A bomb is dropped from the aeroplane when it directly above a target at a height of 1960m.The aeroplane is moving horizontally with a speed of 540k. By how much distance will the bomb miss the target
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540 kmph = 540 × 5/18 = 150 m/s
Time taken to reach ground
t = sqrt(2H / g)
= sqrt(2 × 1960 / 9.8)
= 20 seconds
Horizontal distance = Horizontal speed × Time
= 150 m/s × 20 s
= 3000 m
= 3 km
Bomb will miss the target by 3 km
Time taken to reach ground
t = sqrt(2H / g)
= sqrt(2 × 1960 / 9.8)
= 20 seconds
Horizontal distance = Horizontal speed × Time
= 150 m/s × 20 s
= 3000 m
= 3 km
Bomb will miss the target by 3 km
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