Question

A bomb moving with velocity
40î +50j +25k explodes into two pieces of
masses in the ratio 1 : 4. If the small piece
goes out with velocity 200î + 70j-15k m/s
then the velocity of larger piece after
explosion is​

Answer 1

Answer:

The explosion happened is due to the internal forces. So we can use the conservation of momentum for the system.

Final momentum of the particles = initial momentum of the particles

Let the mass of the bomb be '5m'… with initial velocity '40i + 50j + 25k'

Aftet blast it got divided in particles of mass, 'm' with velocity '200i + 70j - 15k' and '4m' with velocity 'v'

m*(200i + 70j - 15k) + 4m*v =

5m*(40i + 50j + 25k)

Cancel m on both sides

200i + 70j - 15k + 4v = 200i + 250j +125k

4v = 180j + 140k

v = 45j + 35k (the velocity of large mass)