Question

A bomb of 12 kg explodes into pieces of mass 4kg and 8 kg. The velocity of
8 kg mass is 6 m/s. The velocity of the other mass is :
(a) 3 m/s
(b) 12 m/s (c)-12 m/s (d)-3 m/s​

Answer 1

Answer:

according to conservation of momentum

m1v1=m2v2

Explanation:

6m/s*8kg=4kg*v2

$\frac{48}{4}$=v2

v2=12m/s in opposite direction

correct option is (c)