Question

a bomb of 12 KG was sent up higher in the air at the highest point it explodes into 3 fragments of masses. in the ratios 3:1:2 after explosion flew up in the air with velocity of 3m/s,12m/s and 8m/s. calculate the total energy posses by the fragments​

Answer 1

ANSWER

K2K1=2m2p222m1p12

Since p1=p2

⇒K2K1=m1m2⇒K2216=13⇒K2=3216=72J

Momentum of heavier fragment

p2=2m2K2

m2=43×12=9kg

Answer 2

Answer:

ANSWER

K

2

K

1

=

2m

2

p

2

2

2m

1

p

1

2

Since p

1

=p

2

⇒

K

2

K

1

=

m

1

m

2

⇒

K

2

216

=

1

3

⇒K

2

=

3

216

=72J

Momentum of heavier fragment

p

2

=

2m

2

K

2

m

2

=

4

3

×12=9kg

∴p

2

=

2×9×72

=36kgm/s