Physics, asked by madhusgowda5453, 1 year ago

A bomb of 12kg divides in two parts whose ratio of masses is 1:3. if kinetic energy of smaller part is 216j then momentum of bigger part in kg m /s will be

Answers

Answered by aparna64

12

use this formula p=h/✓2m×K.E ..
you will get the answer...

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