Question

a bomb of 18kg explodes into 12 and 6kg. the velocity of 12kg is 5m/s. the k.e of the other piece is​

Answer 1

Answer:

486J

Explanation:

Momentum is conserved just before and after the explosion of the bomb.

Initial momentum is zero, so the resultant momentum of the exploded pieces should be zero.

That is m

1

v

1

=m

2

v

2

⇒(18)(6)=12(v

2

)

⇒v

2

=9m/s

∴ the KE of 12kg mass=

2

1

12(9

2

)=486J

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