Question

A bomb of mass 12 kg explodes into two pieces of masses 4 kg and 8kg. The Velocity of 4kg is 20m/s. Find the velocity of 8kg

Answer 1

Answer:

10m/s

Explanation:

I have attached solution in the image.

Answer 2

Answer:

By law of conservation of moment conservation:  

initial momentum =final momentum  

12 x 0 = (4xv) + (8 x6)  

So v= 48/4 =12m/s  

Hence the piece having 4kg mass will move with 12m/s in opposite direction of the piece having mass 8kg  

now the KE of 4kg piece= 12x(mv^2) =(1/2)x 4 x 12^2 = 288J