A bomb of mass 3.0 kg explodes in air into two
pieces of masses 2.0 kg and 1.0 kg. The smaller
mass goes at a speed of 80 m/s. The total energy
imparted to the two fragments is -
(1) 1.07 kJ
(2) 2.14 kJ
(3) 2.4 kJ
(4) 4.8 kJ
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Answer:
4.8kj
Explanation:before and after explodes the momentum is always conserved.
P1=p2
M1v1=m2v2
1*80=2*x
X=40m/s
Energyof both the particles=energy of one particle+energy of another particle
=1/2m1v1^2+1/2m2v2^2
=1/2*1*80*80+1/2*2*40*40
=3200+1600
=4800
4.8KJ
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