Question

A bomb of mass 30 kg at rest explodes into two pieces of masses 18 kg and 12 kg. the velocity of 18 kg mass is 6 ms-1. the ke of other mass is

Answer 1

k.E=1 m v sqaure and so put value mass and velocity in formula so K.E=1 upon 2*30*12 square so answer is 2160joule hope it helps

Answer 2

Question:

A bomb of mass 30 kg at rest explodes into 2 pieces of masses 18 kg and 12 kg the velocity of 18 kg mass is 6 m/s the KE of the other mass will be ?

Answer:

486 J

Explanation:

The linear momentum of the exploding part will remain conserved.

Applying Conservation of linear momentum,

m₁u₁ = m₂u₂

here,

m₁ = 18 kg

m₂ = 12 kg

u₁ = 6 m/s

u₂ = ?

u₂ = 18×6÷12 = 9 m/s

u₂ = 9 m/s

Now, The kinetic energy of 12 kg mass

K.E₂ = m₂u₂²/2 = 12×(9)²/2 = 6×81 = 486 J