A bomb of mass 5 kg explodes in to two pieces from rest. After the explosion one piece of 3 kg moves with 60 m/s. Find the speed of second part?
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Answered by
1
Answer:
90m/s
Explanation:
m1.u1+m2u2=m1.v1+m2.v2
and as it's starting from rest the LHS will be zero andnow put the other value in the RHS
3×60+2×X
=180+2X
180=2X
X=180/2
=90M/S
Answered by
1
Therefore, the velocity of another piece is
90 m/s.
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