Question

A bomb of mass 5 kg is at resr explodes into 3 parts with masses 2,2,1 kg .with velocities 5 m/s and 6m/s respective ly .find velocity of the third mass?

Answer 1

Answer:22m/s

Explanation:M=5kg u=0

initial P = Mu=0

m1=2kg m2=2kg m3=1kg

v1=5m/s v2=6m/s

By law of conservation of momentum;

Mu=m1v1+m2v2+m3v3

=> 0=2×5+2×6+1v3

=> 0=10+12+v3

=> 0=22+v3

v3 = -22m/s

(Negative because opposite direction)