Question

) A bomb of mass 50 kg at rest explodes into two pieces of masses 40 kg and

10 kg . The velocity of bigger piece is zero then velocity of smaller piece is

___ms-1

.
​

Answer 1

Given :

• Mass of the bomb = 5 kg
• Masses of the individual pieces = 40 kg and 10 kg
• Velocity of bigger piece is zero

To Find :

• The velocity of the smaller piece

Solution :

Here , the momentum before and after the explosion is conserved. This mean ,

• m₁v₁ = m₂v₂

Here we have ;

• m₁ = 40 kg , v₁ = 0 m/s
• m₂ = 10 kg , v₂ = v₂ (let)

➙ (40)(0) = (10)(v₂)

➙ 0 = 10v₂

➙ v₂ = 0/10

➙ v₂ = 0 m/s

Hence ,

• The velocity of the smaller piece is 0 m/s.

Answer 2

Correct Question-:

• A bomb of mass 50 kg at rest explodes into two pieces of masses 40 kg and 10 kg . The velocity of bigger piece is zero then Find velocity of smaller piece .

AnswEr -:

• $\boxed{\purple{\sf{\star{The\:velocity \:of\:bigger \:piece \:or (velocity)_{2}\:is\:-:0\:m/s}}}}$

Explanation-:

Given ,

• A bomb of mass 50 kg at rest explodes into two pieces of masses 40 kg and 10 kg .
• The velocity of bigger piece or velocity of 40 kg exploded bomb is zero m/s

To Find ,

• The velocity of smaller piece or velocity of 10 kg exploded bomb .

Solution-:

☆ According to Conservation law of momentum.

• $\boxed{\blue{\sf{\star{\:Conservation \:law\:of\:Momentum\:-:"(mass)_{1}(velocity)_{1}= (mass)_{2}(velocity)_{2}"}}}}$

Or ,

• $\boxed{\blue{\sf{\star{\:Conservation \:law\:of\:Momentum\:-:"m_{1}v_{1}= m_{2}v_{2}"}}}}$

Here ,

• ( Mass )¹ -: The mass of bigger piece in which bomb is exploded or m¹ = 40 kg .
• ( Velocity)¹ -: The velocity bigger piece in which bomb is exploded or v¹ = 0 m/s .
• ( Mass )² -: The mass of smaller piece in which bomb is exploded or m² = 40 kg .
• ( Velocity)² -: The velocity bigger piece in which bomb is exploded or v² = ?

Now ,

• $\pink{\sf{\rightarrow { 50 \times 0 = 10 \times v_{2}}}}$
• $\pink{\sf{\rightarrow { \frac { 50 \times 0 }{10}= v_{2} }}}$
• $\pink{\sf{\rightarrow { \frac { 0 }{10}= v_{2} }}}$
• $\pink{\sf{\rightarrow { 0 m\s= v_{2} }}}$

Therefore,

• $\boxed{\purple{\sf{\star{\:v_{2}\:or (velocity)_{2}-:0\:m/s}}}}$

Hence ,

• $\boxed{\purple{\sf{\star{The\:velocity \:of\:bigger \:piece \:or (velocity)_{2}\:is\:-:0\:m/s}}}}$

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