Question

A bomb of mass 6kg initially at rest explodes into two fragments of masses 4kg and2kg respectively. If the greater mass moves with a velocity of 5m_s, find the velocity of 2kg mass

Answer 1

Answer:

-10m/s

Explanation:

Here we will use the principle of conservation of linear momentum

the 4 kg mass is moving with 5 metre per second

so it's linear momentum is 20 Newton second

Shobha conservation of linear momentum the momentum of second particle should be -20 Newton second

change the mass of the second particle is to kilograms so its speed should be -10 metres per second

Answer 2

Answer:

-10m/s

Explanation:

Let the velocity of the other part be y,  

Now,

     IM=FM                                            [IM = Initial Momentum,

=>  6 x 0 = (4 x 5) + (2 x y)                    FM = Final Momentum]

=>  0 = 20 + 2y

=> 0-20 = 2y

=> -20 = 2y

=> -20/2 = y

=> -10 = y                                            

Hence the value of the velocity of the other part, of mass 2kg, is equal to -10m/s, and the velocity's value is in negative as it is in the opposite direction of the other part, of mass 4kg.