Question

A bomb of mass 8 kg at rest explodes in three fragments. Two equal masses of 2kg each fly off at 20 m/s perpendicular to each other. Find magnitude and direction of velocity of third fragment.

Answer 1

Answer:

10√2 m/s

According to Law of Conservation of Linear momentum

MV = m1v1 + m2V2 + m3v3

V= 0

0 = 40i + 40j + 4v

v = -10i -10j

|V| = 10√2

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