A bomb of mass 9 kg explodes into two pieces of 3 kg and 6 kg. The velocity of the 3 kg piece is 16m/s. What is the kinetic energy of the 6 kg piece?
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Answer:
192 joules
Explanation:
this question is based on conservation of momentum
mu=m1v1+m2v2
9(0)=3(16)+6(x)..............let x be velocity of 6 kg piece
x=8m/s
now kinetic energy of 6 kg piece is=1/2 mv^2=1/2(6)(8)(8)=192 joules
hope it helps..
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