Question

a bomb of mass m at rest explodes into two parts of masses m/3 and 2m/3, which move opposite to each other. If the velocity of the lighter part is 'v', then the velocity of the heavier part is

Answer 1

Answer:

7m2

Explanation:

this velocity is the highlighter part of V and the velocity of the highest heavier part is a 75 mm to pixels to parts of the masses is 5 by 3 and 2 a.m. by 3 and if we divide with the power of m into three on the device and we divide it by in 27 so we will get it right 7m 2

Answer 2

A bomb of mass m at rest explodes into two parts of masses m/3 and 2m/3, which move opposite to each other. If the velocity of the lighter part is 'v', then the velocity of the heavier part is

Explodes into two parts of masses m/3 and 2m/3 .

If the velocity of the lighter part is 'v', then the velocity of the heavier part is :

Conservation of momentum

0 = m/3 ×v - 2m/3 ×[(V1)

= v/2 = V1

Then the velocity of the heavier part is : v/2