a bomb of mass M is projected from the ground with speed v at angle theta with the horizontal at the maximum height from the ground it explodes into two fragments of equal mass if one fragment comes to rest immediately after explosion then the horizontal range of centre of mass is
Answers
Answer:
Horizontal range of the centre of mass is v²sin2∅/g.
Explanation:
Let us assume that the bomb was projected and it did not explode. Then, the bomb would have come to a ground after a time of flight. In which case, the horizontal range of the unexploded bomb would have been v²sin2∅/g.
Now, we know that bomb exploded not because of the any external force acting on it, but due to the internal forces of the bomb. So, in this case the net external force remains zero.
We know that, when the net external force is zero, the velocity of a body remains constant. Which in turn implies that the centre of mass remains at its original position even after collision.
Hence, the bomb before and after collision will move with the same constant velocity v. That implies that the horizontal range remains the same even if the bomb explodes. So, the horizontal range of the centre of mass is v²sin2∅/g.
Hope it helps! ;-))