Question

A bomber plane moves horizontally with a speed of 500 and a bomb released from it strikes the ground in 10s find the angle at which it strikes the ground

Answer 1

the bomb is dropped  , therefore its horizontal velocity = 500 

and vertical velocity = 0

in 10 sec 

 v = u + at 

   = 0 + 10x10

    = 100 m/s

horizontal velocity remains unchanged  bcoz there''s no accn  in the horizontal 

therefore 

tan Θ =  ( vertical velocity )/ (horizontal velocity )  = 1/5


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