A bomber plane moves horizontally with a speed of 500 and a bomb released from it strikes the ground in 10s find the angle at which it strikes the ground
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the bomb is dropped , therefore its horizontal velocity = 500
and vertical velocity = 0
in 10 sec
v = u + at
= 0 + 10x10
= 100 m/s
horizontal velocity remains unchanged bcoz there''s no accn in the horizontal
therefore
tan Θ = ( vertical velocity )/ (horizontal velocity ) = 1/5
Hope it helps you and pls mark as brain list
and vertical velocity = 0
in 10 sec
v = u + at
= 0 + 10x10
= 100 m/s
horizontal velocity remains unchanged bcoz there''s no accn in the horizontal
therefore
tan Θ = ( vertical velocity )/ (horizontal velocity ) = 1/5
Hope it helps you and pls mark as brain list
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