Physics, asked by satyansh40606, 5 hours ago

A bomber plane moves horizontally with a speed of 500 m/s and a bomb released from it, strikes the ground in 10 sec. Angle at which it strikes the ground will be (g = 10 m/s2)
(A) tan–1(1\5)
(B)tan-1(-1\5)
(C) tan–1(1)
(D) tan–1(5)
.
.
where my answer is wrong????????​

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Answered by dishi2007
1

Answer:

(C) tan–1(1)

Explanation:

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Answered by Anonymous
0

Answer:

  • A bomber plane moves horizontally with a speed of 500 m/s and a bomb released from it, strikes the ground in 10 sec. Angle at which it strikes the ground will be (g = 10 m/s2)

Explanation:

  • hope it helps you!
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