A bomber plane moves horizontally with a speed of 500 m/s and a bomb released from it, strikes the ground in 10 sec. Angle at which it strikes the ground will be (g = 10 m/s2)
(A) tan–1(1\5)
(B)tan-1(-1\5)
(C) tan–1(1)
(D) tan–1(5)
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where my answer is wrong????????
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Answered by
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Answer:
(C) tan–1(1)
Explanation:
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Answer:
- A bomber plane moves horizontally with a speed of 500 m/s and a bomb released from it, strikes the ground in 10 sec. Angle at which it strikes the ground will be (g = 10 m/s2)
Explanation:
- hope it helps you!
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