A book contains 1000 pages. A page is chosen at random. Find the probability that the sum of the digits of the marked number on the page is equal to 9.
Answers
the probability that the sum of the digits of the marked number on the page is equal to 9 = 11/200 = 0.055
Step-by-step explanation:
Book Contains 1000 Pages
Sum of Digits = 9
1 Digit - 9 ( 1 Such number)
2 Digit 18 , 27 , 36 .............................., 81 , 90 ( 9 such number)
upto 2 Digits 1 + 9 = 100 Such numbers
3 Digit
108 , 117 , 126 , .......................... . 180 , ( 9 such number)
207 , 216 , 225 ................................270 ( 8 such numbers)
306 , 315 ..........................................360 (7 Such numbers)
405 , 414 .........................................450 (6 Such numbers)
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801 , 810 ( 2 Such numbers)
900 ( 1 Such number)
Total such numbers
= 10 + 9 + 8 + ......................................................+ 2 + 1
= 55
Probability = 55/1000 = 11/200 = 0.055
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